5v^2=13v-6

Solution for 5v^2=13v-6 equation:

5v^2=13v-6

We move all terms to the left:

5v^2-(13v-6)=0

We get rid of parentheses

5v^2-13v+6=0

a = 5; b = -13; c = +6;
Δ = b2-4ac
Δ = -132-4·5·6
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-7}{2*5}=\frac{6}{10}
=3/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+7}{2*5}=\frac{20}{10}
=2
$